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pks array going from 2 arguments to 1

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Alvin
Alvin 2017 年 8 月 7 日
コメント済み: Alvin 2017 年 8 月 7 日
clear
g1 = 1;
g2 = 0;
k1 = 0.2;
k2 = 0.1;
n1 = 0;
n2 = 0;
nm = 0;
D = 1;
O = -1;
gam = 0.2;
alph = 0;
C2 = (4.*(abs(g2).^2))./(k1.*k2);
w = (-10:0.1:10);
Pa = (-1i.*w) + (k1/2).*(1+C2);
Pb = (-1i.*w) + (gam/2);
Y1 = (-1i.*g1.*sqrt(k1))./(Pa.*Pb + g1.^2);
Y2 = (-g1.*sqrt(k1.*C2).*exp(1i.*alph))./(Pa.*Pb + g1.^2);
Y3 = (Pa.*sqrt(gam))./(Pa.*Pb + g1.^2);
AY1 = abs(Y1).^2;
AY2 = abs(Y2).^2;
AY3 = abs(Y3).^2;
Sbb = 2*pi.*((abs(Y1).^2).*(n1 + 0.5) + (abs(Y2).^2).*(n2 + 0.5) + (abs(Y3).^2).*(nm + 0.5));
[pks,locs] = findpeaks(Sbb);
Diff = abs(w(locs(1))-w(locs(2)));
figure(1)
plot(w,Sbb)
Running the code above generates a plot with 2 peaks. But as g2 increases, the peaks slowly vanishes/merges into one peak. I intend to find the peak separation as a function of g2 and this is shown in my Diff that I defined.
My issue is of the following: As g2 increases and eventually turns from two peaks into one, Diff cannot be computed since there is only one peak. So I get an error saying Index exceeds matrix dimensions. How can I resolve this by just letting the Diff = 0 the moment it has turn into one peak? (since there are no longer two peaks and so the peak separation should be 0)
I hope my question is clear and I would appreciate any help. Thank you in advance.

採用された回答

Kevin Xia
Kevin Xia 2017 年 8 月 7 日
Try the following:
[pks,locs] = findpeaks(Sbb);
if numel(pks)==2
Diff = abs(w(locs(1))-w(locs(2)));
elseif numel(pks)==1
Diff=0;
end
figure(1)
plot(w,Sbb)
  1 件のコメント
Alvin
Alvin 2017 年 8 月 7 日
Thanks! That worked.

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