Different Results when calling feval

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EmaG
EmaG 2017 年 8 月 7 日
回答済み: Walter Roberson 2017 年 8 月 7 日
Hi all,
When I call my function in a parfor loop via feval it just returns zeros.
The same setting but without parfor returns the actual and correct results of the function. I just checked it going through the built-in genetic algorithm functions step by step when 'UseParallel' is set as true (whilst 'UseVectorized' already set as false).
What am I missing? How does the structure of my handled function affect the result? Unfortunately, I can not paste here the body of the function.
Thanks in advance!
  1 件のコメント
Jan
Jan 2017 年 8 月 7 日
It is impossible to guess, why the code does, what it does, without seeing it. If you cannot show us the code, helping is based on guessing.

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採用された回答

Walter Roberson
Walter Roberson 2017 年 8 月 7 日
Global variables and persistent variables are not copied into the clients of parfor workers.

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