create a specific vector from excel file

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MUKESH KUMAR
MUKESH KUMAR 2017 年 8 月 4 日
コメント済み: Jan 2017 年 8 月 9 日
I want create a zero vector (1*24) and according to the appliances like for 'lights' (in Excel file ) create A1 zero vector (1*24) ,start and end time shows that A1 zero vector replace power value of 0.5 between 18-24 in row vector but the condition is that this 0.5 values put only 6 places randomly between 18-24. And similarly for all appliances. Like PHEV A17 vector it should contain 2.5 power value at 20-21-22-23-24-1-2-3-4-5-6 only for 4 (hours ) place randomly at any place between 20-6 .
  3 件のコメント
MUKESH KUMAR
MUKESH KUMAR 2017 年 8 月 4 日
read the attached excel file there and i assume A1 vector for lights and A2 for refrigerator ,A3 for electric stove and so on....... output should be like A1=[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.5 0 0.5 0.5 0.5 0.5]; A2=[0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125 0.125];%0.125 placed between 1-24 in 1*24 vector only for 24 hours(G2 value in excel). A3=[0 0 0 0 0 0 1.5 1.5 0 0 1.5 0 0 0 0 0 0 0 0 0 0 0 0 0];% 1.5 placed between 6-14th in 1*24 vector only for 3hours(G3 value in excel).

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採用された回答

KL
KL 2017 年 8 月 8 日
If I understood correctly, the following is what you're looking for. It's basically the same as Jan's but I just did it for the rest of the data from your excel file
data = xlsread('apdata.xls');
data_len = length(data);
A = zeros(18,data_len);
fi = @(a,b) ([a:data_len 1:b]);
for i = 1:data_len
pVec = data(i,3)*ones(data(i,5),1);
if(data(i,1)<data(i,2))
ind = data(i,1):data(i,2);
else
ind = fi(data(i,1),data(i,2));
end
x = randperm(numel(ind));
x = x(1:data(i,5));
A(i,ind(x)) = pVec;
end
  2 件のコメント
MUKESH KUMAR
MUKESH KUMAR 2017 年 8 月 8 日
thanks 100% right that I need ,I got from matrix A .
MUKESH KUMAR
MUKESH KUMAR 2017 年 8 月 9 日
but if I create a matrix for a single value of 'i' without loop then its create only vector A size 18*18 but i require A vector of 18*24 or 1*24 for single value of 'i'. explain the following code:
fi = @(a,b) ([a:data_len 1:b]);

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その他の回答 (1 件)

Jan
Jan 2017 年 8 月 4 日
All I understand from the question is: "0.5 values put only 6 places randomly between 18-24":
A1 = zeros(1, 24);
index = 18:24;
index = index(randperm(1:7, 6));
A1(index) = 0.5;
Easier:
A1 = zeros(1, 24);
A1(18:24) = 0.5;
A1(randi([18, 24], 1)) = 0;
I have no idea, what the rest of the question means.
  4 件のコメント
MUKESH KUMAR
MUKESH KUMAR 2017 年 8 月 8 日
still did not understand my question?
Jan
Jan 2017 年 8 月 9 日
No, I do not understand it. "simillary for all appliances like for 'TV' (in Excel file )" What is a "appliance", what is "TV", what does "in Excel file" mean? What is an "A5 zero vector (1*24)"? "start and end time shows that A1 zero vector replace power value of 0.25 between 16-24"?
Sorry, I do not understand any sentence of the explanation. If KL#s answer solves your problem, it is not worth to explain it again.

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