Element by element (xor) operation on cells.
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I have two variables, Test and Train.
Test = cell of dimension 10 x 1 and
Train = cell of dimension 20 x 1
All elements are logical.
I want an operation similar to matrix multiplication, except that I want xor, instead of multiplication.
All of the 100 elements in Test should be xor(ed) with each of the 2000 elements in Train. All the while, I was doing this using for loop, but I want to avoid for loops now. I was trying to figure out performing this using bsxfun, but couldn't get it as desired. What is the most efficient way to do this?
5 件のコメント
James Tursa
2017 年 8 月 2 日
Loops is probably the way to go here. You could potentially pull things out via cell2mat, do the calculations, and then use cell2mat to get your result, but why bother with all of that data copying? Using loops is straightforward and easy to read.
回答 (1 件)
Akira Agata
2017 年 8 月 2 日
I think cellfun would be suitable to this, like:
load('Train&Test.mat');
Result = cell(numel(Test), numel(Train));
for kk = 1:numel(Train)
Result(:,kk) = cellfun(@xor, repmat(Train(kk),numel(Test),1), Test,...
'UniformOutput', false);
end
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