MATLAB Answers


YAxis Exponent doesnt change after flipping YTick

David Pyles さんによって質問されました 2017 年 7 月 27 日
最新アクティビティ Walter Roberson
さんによって コメントされました 2017 年 7 月 31 日
I need to reverse the yaxis index, then flip the image. However the exponential disappears after the YDir is set to 'Reverse'. The MATLAB suggested dot notation is not working in the following example that should accomplish all of these tasks:
open 'myfig.fig'
figure(1); subplot 311; % I don't think this matters here, but maybe doing this in a subplot is an issue
yTicks = get(gca, 'YTick'); % get yaxis index
yTicksReverse = sort(yTicks, 2, 'descend'); % reverse yaxis index
set(gca, 'YTickLabel', num2str(yTicksReverse')); % set reversed index to figure
set(gca, 'YDir', 'reverse'); % flip image, along with the y axis.
ax = gca;
ax.YAxis.Exponent = 6;
After this code is run, looking at the ax.YAxis values does show that the exponent assignment has been set to 6, however it does not change on the figure itself :(

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1 件の回答

回答者: Shruti Shivaramakrishnan 2017 年 7 月 31 日
編集済み: Walter Roberson
2017 年 7 月 31 日

Also, if it is helpful, converting the Tick values to a decimal value can be done using :
>> ax.XAxis.TickLabelFormat = '%.60f';
Then if you'd like the Exponent to be displayed:
>> ax.XAxis.Exponent = 6;

  3 件のコメント

David Pyles 2017 年 7 月 31 日
Thanks, but that doesn't help. Once YDir is flipped the dot notation no longer works.
Steven Lord
2017 年 7 月 31 日
Define "no longer works" -- does it throw an error? If so what is the FULL text of the error message? Does it issue a warning? Ditto on the full message in that case. Does it do something else (and if so, describe what EXACTLY it does.)
Walter Roberson
2017 年 7 月 31 日
Question: is this XAxis Exponent or YAxis Exponent that we are talking about?
The use of the axis exponent is disabled when you set tick labels manually.

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