Do a cross-set operation on a matrix

I have a matrix which looks as follows:
[1 2 3;
4 5 6]
I want to do a cross-set operation on itself, so that each element is associated with every other element, like this:
[1 2 3;
4 2 3;
1 5 3;
4 5 3;
1 2 6;
4 2 6;
1 5 6;
4 5 6]
Can someone please help me/point me in right direction?

 採用された回答

Sean de Wolski
Sean de Wolski 2012 年 4 月 10 日

0 投票

A = [1 2 3; 4 5 6]; %data
[xx yy zz] = meshgrid(1:2,3:4,5:6); %column-wise linear indices
B = [A(xx(:)) A(yy(:)) A(zz(:))] %extract
More - generalized to n-dimensions and rows:
A = [1 2 3 7; 4 5 6 9]; %data
[nr nc] = size(A);
C = num2cell(reshape(1:(nr*nc),nr,nc),1);
X = cell(nc,1);
[X{1:nc}] = ndgrid(C{:}); %column-wise linear indices
for ii = nc:-1:1
V(:,ii) = A(reshape(X{ii},[],1));
end

5 件のコメント

Vinay Pandey
Vinay Pandey 2012 年 4 月 10 日
Can this be extended to matrix with 'n' number of columns?
Sean de Wolski
Sean de Wolski 2012 年 4 月 10 日
sure.
Vinay Pandey
Vinay Pandey 2012 年 4 月 10 日
What I mean to ask was, how can we extend it to n-columns, when we don't know the number of columns in advance.
Sean de Wolski
Sean de Wolski 2012 年 4 月 10 日
see edit
Vinay Pandey
Vinay Pandey 2012 年 4 月 10 日
Thanks!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

ヘルプ センター および File ExchangeCreating and Concatenating Matrices についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by