convert decimal values to binary?

xa(1)=0;
ya(1)=0;
a=1.4;
b=0.3;
sa=0;

for i=2:41616
    xa(i)=1-a*(xa(i-1)^2)+ya(i-1);
    ya(i)=b*xa(i-1);

sa(i) = mod (ya(i)* (10^12) , 256);

sabinary(i) = dec2bin(round(sa(i) * (2^10)), 8) - '0';
end

This is the code to find 'sa'. I got values for sa(i) but i cant convert those values of 1D array to binary. Please help me with the above code.

[Stephen23]

@SNEHA P S: what do you expect the output to be? How do you expect to put a non-scalar char vector (the output from dec2bin) into one single element of sabinary ?

Answer 1

[Walter Roberson]

The following is for R2016b or later, specifically to use a facility that allows the entire binary value to be stored into a single location, since that is how you seem to expect the output to be.

xa(1)=0;
ya(1)=0;
a=1.4;
b=0.3;
sa=0;
N = 41616;
sabinary = strings(1, N);
sabinary(1) = string('00000000');
for K = 2:N
    xa(K)=1-a*(xa(K-1)^2)+ya(K-1);
    ya(K)=b*xa(K-1);
    sa(K) = mod (ya(K)* (10^12) , 256);
    sabinary(K) = string(dec2bin(round(sa(K) * (2^10)), 8));
end

sa_recovered = bin2dec(sabinary) / 2^10;

[SNEHA P S]

Thank u