What (%.5g\n) does mean?

disp(['PSNR ' num2str(measerr(CoverImg,s))])
[~, MSE] = measerr(CoverImg,s);
fprintf('MSE: %.5g\n', MSE)

the result is

PSNR 44.6192

 MSE: 2.2447

I want MSE : 0.22447 What I must do?

Answer 1

[Sebastian Castro]

The format string will indicate the display precision -- up to 5 decimal points.

What you're asking is to actually divide the value of MSE by 10... I am sure the following code will give you what you want, but you're manipulating your results and this is likely wrong.

fprintf('MSE: %.5g\n', MSE/10)

- Sebastian