round robin

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Ayda
Ayda 2012 年 4 月 7 日
Good Morning\evening i have to write a code for round robin(example 5 processes) i have number of processes and each process has its CPUtime(10,6,2,4 and 8 respectively)
i could not know why the CPUtime for process 4 and 5 do not go to zero
numOfJobs=input('Enter the number of jobs to run = ');
for i=1:numOfJobs
job(i)=i;
end
CPUtime=input('Enter the CPU time required by each job = ,[in vector form] ');
totalCPUtime= sum(CPUtime)
while (totalCPUtime ~= 0)
for i=1:numOfJobs
if (CPUtime(i)== 0)
break
else
CPUtime(i)=CPUtime(i)-1;
end
job(i)
end
totalCPUtime=totalCPUtime-1;
end

回答 (1 件)

Walter Roberson
Walter Roberson 2012 年 4 月 7 日
TotalCPUtime needs to be recomputed as sum(CPUtime). Your "for i" loop can end up decrementing more than one CPUtime entry, so your total does not get decremented by exactly 1 under most circumstances.
  2 件のコメント
Walter Roberson
Walter Roberson 2012 年 4 月 8 日
Your present code initializes totalCPUtime as the sum of the CPUtime . You then change what could be several of the CPUtime (all the non-zero ones), but your code only decreases totalCPUtime by 1 rather than by 1 per CPUtime that was decreased.

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