FCFS code

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Ayda
Ayda 2012 年 4 月 7 日
回答済み: Sanjana 2024 年 3 月 5 日
Good Morning\ Evening
I have number of processes and each process has its arrival time the question require to simulate processes using First Come First Serve.
I wrote this code for FCFS but did not return a correct values the result should display the order of FCFS
numOfJobs=input('Enter the number of jobs to run = ');
for i=1:numOfJobs
job(i)=i;
end
job1=job;
arrivalTime=input('Enter the arrival time of each job = ,[in vector form] ');
for i=1:numOfJobs-1
y=i+1;
for j=y:numOfJobs
if(arrivalTime(j)<arrivalTime(i))
firstcome=job(j);
job(j)=job(i);
job(i)=firstcome;
end
end
end
job;
out2=[out1 arrivalTime']
Also I have to figure out the starting time, the completion time and total waiting Time for each process

回答 (2 件)

Walter Roberson
Walter Roberson 2012 年 4 月 7 日
You can replace most of what you have written with
[sortedArrivalTimes, job] = sort(arrivalTime);
It is not possible to work out the starting and completion and waiting times without knowing how long each job takes. Other than that you can say that the starting time for the first job to arrive will be sortedArrivalTimes(1)
  2 件のコメント
Ayda
Ayda 2012 年 4 月 7 日
thank you very much
but if I want to use the for loop,, where is the mistake
Walter Roberson
Walter Roberson 2012 年 4 月 7 日
Using bubble sort is a mistake more often than not...

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Sanjana
Sanjana 2024 年 3 月 5 日
numOfJobs=input('Enter the number of jobs to run = ');
for i=1:numOfJobs
job(i)=i;
end
job1=job;
arrivalTime=input('Enter the arrival time of each job = ,[in vector form] ');
for i=1:numOfJobs-1
y=i+1;
for j=y:numOfJobs
if(arrivalTime(j)<arrivalTime(i))
firstcome=job(j);
job(j)=job(i);
job(i)=firstcome;
end
end
end
job;
out2=[out1 arrivalTime']

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