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Is there a way to replace a specific NaN elements by integer where isnan would not work with steps greater than 1?

1 回表示 (過去 30 日間)
Abdulaziz Abutunis
Abdulaziz Abutunis 2017 年 7 月 4 日
閉鎖済み: MATLAB Answer Bot 2021 年 8 月 20 日
Hello All,
Could you please help with this problem
I have this matrix
hh=[NaN 1 2 3 4;3 5 66 NaN 6;NaN 3 4 7 NaN; 9 NaN 8 2 NaN];
and I want to replace only the NaN in some places to an integer. I have tried this hh(isnan(hh(1:2:4,1)))=1; which should replace the NaN in element (3,1) by 1 but did not work

回答 (1 件)

Walter Roberson
Walter Roberson 2017 年 7 月 4 日
mask = isnan(hh(:, 1)); mask(2:2:end) = false;
hh(mask) = 1;
  2 件のコメント
Abdulaziz Abutunis
Abdulaziz Abutunis 2017 年 7 月 4 日
Thank you Walter, I tried your example and it will replace all the NaN in the first column. Best
Walter Roberson
Walter Roberson 2017 年 7 月 5 日
isnan(hh(1:2:4,1)) is true for hh(1,1) so you have indicated that you do want hh(1,1) to be replaced.

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