Check and eliminate rows based on conditions 2

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yue ishida
yue ishida 2017 年 7 月 4 日
コメント済み: yue ishida 2017 年 7 月 4 日
Hi. I have a matrix as below. I need help to code this problem.
A =
[1.0000 -0.1367 0.0366 0.2431 0.1541 0.2263 0.3913 -0.1903
-0.1367 1.0000 -0.3278 -0.1718 -0.3803 -0.1378 -0.0839 0.2210
0.0366 -0.3278 1.0000 0.2087 0.4730 0.2077 0.0717 -0.1989
0.2431 -0.1718 0.2087 1.0000 0.2513 0.3382 0.5135 -0.3838
0.1541 -0.3803 0.4730 0.2513 1.0000 0.1547 0.0867 -0.1398
0.2263 -0.1378 0.2077 0.3382 0.1547 1.0000 0.5096 -0.4888]
1. Therefore, I have to check every row in third column.
2. For every row in third column, I have to ensure that all previous rows have more value than current row value. If any previous row value in third column is less than current value, that previous row will be eliminated. Else, previous row will maintain.
3. For matrix A, as result, all rows except row 3, 5, and 6 will eliminate. End result after check and eliminate will produce matrix B as below.
A =
0.0366 -0.3278 1.0000 0.2087 0.4730 0.2077 0.0717 -0.1989
0.1541 -0.3803 0.4730 0.2513 1.0000 0.1547 0.0867 -0.1398
0.2263 -0.1378 0.2077 0.3382 0.1547 1.0000 0.5096 -0.4888
  2 件のコメント
Image Analyst
Image Analyst 2017 年 7 月 4 日
"For every row in third column, I have to ensure that all previous rows have more value than current row value. If any previous row value in third column is less than current value, that previous row will be eliminated." <=== that is contradictory. The second sentence contradicts the first. Previous rows NEED to be less than the current row or else the third column will not monotonically increase. If you REMOVE the previous row, you are no longer guaranteed that each row will be more than the above row.
yue ishida
yue ishida 2017 年 7 月 4 日
actually, that's the point of this algorithm...

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採用された回答

Andrei Bobrov
Andrei Bobrov 2017 年 7 月 4 日
編集済み: Andrei Bobrov 2017 年 7 月 4 日
[~,ii] = sort(A(:,3),'descend');
for MATLAB >= R2016b
out = A(ii(all(tril(ii < ii')==0,2)),:);
for MATLAB <= R2016a
out = A(ii(all(tril(bsxfun(@lt,ii(:),ii(:)'))==0,2)),:);

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