how to average specific rows of all columns?
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i am having 100x32 matrix in my data set. i would like to average 20 rows of all columns, like first 20rows average, next 20 and so..on...
can any one help in this problem.
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the cyclist
2017 年 6 月 10 日
編集済み: the cyclist
2017 年 6 月 10 日
% Some made-up data
A = rand(100,32);
N = 20;
movingAverageA = movmean(A,[(N-1) 0]); % Trailing average of N rows
output = movingAverageA(N:N:end,:);
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その他の回答 (2 件)
J Yadav
2019 年 1 月 16 日
to take a moving average of 1 to 20 rows, then 21-40 rows, then 41-60 rows etc.
of a data matrix with n rows and m columns.
you may also try:
for i=1:(n/20) % given that n is a multpile of 20 or your choice of no. of rows to average.
a=(i-1)*20+1;
b=(i-1)*20+20;
meandata(i,:) = mean(data(a:b,:),1);
end
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Image Analyst
2017 年 6 月 10 日
編集済み: Image Analyst
2017 年 6 月 12 日
The first index are the rows. For example to average only the first 20 rows
columnMeans = mean(data([1:20], :), 1);
Or to average rows 34, 23, and 194, do
rowsToAverage = [34, 23, 194];
columnMeans = mean(data(rowsToAverage, :), 1);
2 件のコメント
Image Analyst
2017 年 6 月 12 日
This seems to work:
data = randi(9, 100, 32) % Sample 100x32 data
columnMeans = [
mean(data([1:20], :), 1);
mean(data([21:40], :), 1);
mean(data([41:60], :), 1);
mean(data([61:80], :), 1);
mean(data([81:100], :), 1)]
Is that what you want?
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