Non-zero column value

hi if have a matrix like this:

    A=[1,0,0,0;0,1,1,1;0,0,1,0;0,0,1,1]

In this matrix i want to check that apart from diagonal values(1,1 & 2,2 etc.), if there are some other non-zero elements in the row then display that row's index. In A, it should display 2 and 4.

Thanks in advance.

Answer 1

[Image Analyst]

Try eye(), any(), and find():

A=[1,0,0,0;0,1,1,1;0,0,1,0;0,0,1,1]
diagonalElements = logical(eye(length(A)))
% Make copy of A so we don't change 
% the original A (which could be bad).
Acopy = A;
% Set diagonal elements = 0.
Acopy(diagonalElements) = 0
rowsWith1s = find(any(Acopy, 2))

[Tha saliem]

Thankyou very much it really helped. What if i want to get rowWith0s? (Like row 1 and 3 in above example)

[Image Analyst]

You don't need a copy in that case because we don't need to change A, just to check whether the number of 0s is one less than the number of columns.

rowsWith0s = find(sum(A == 0, 2) == size(A, 2)-1)

[Tha saliem]

Yes got it. Thanks alot for helping.