Technically, I have nothing since I don't know where to start. it seems so simple. But i don't know what commands to use
Write a program in a script file that determines the real roots of a quadratic equation
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Howdy, I am new to math lab and need a little help The question asks: "Write a program in a script file that determines the real roots of a quadratic equation ax^2+bx+c=0. Name the file quadroots. When the file runs, it asks the user to input values of the constants a,b, and c. To calculate the roots of the equation the program calculates the discriminant D, given by D=b^2-4ac."
Then it goes on to give me specific equations and what Matlab is actually doing
I don't know what commands to use, and any help would be appreciated, thanks
採用された回答
Thomas
2012 年 4 月 2 日
If you are beginning, this is a good resource. It is a MATLAB tutorial and will help you solve quadratic equations with MATLAB.
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その他の回答 (5 件)
Fikru Dikumbab
2014 年 9 月 16 日
編集済み: Fikru Dikumbab
2014 年 9 月 16 日
% ax^2+bx+c =0 is a quadratic equation
function qadr(a,b,c)
if b^2-4*a*c > 0
r1=(-b+sqrt(b^2-4*a*c))/2*a
r2=(-b-sqrt(b^2-4*a*c))/2*a
else if b^2-4*a*c == 0
r=-b/2*a
else
disp(' No real solution')
end
end
end
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Md. Intesar Farhan Labib
2021 年 4 月 6 日
編集済み: Md. Intesar Farhan Labib
2021 年 4 月 6 日
clc
clear all
close all
a= input("Co-efficient of x^2: ");
b= input("Co-efficient of x: ");
c=input("Contant term: ");
d= b^2-4*a*c;
fx=[a b c];
x=roots(fx);
if d>0
disp(['The equation has two roots ', num2str(x(1)),' ,',num2str(x(2))]);
elseif d==0
disp(['The equation has one root ', num2str(x(1)),',',num2str(x(2))]);
else
disp("The equation has no real roots.");
end
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Shailendra Shankar
2023 年 4 月 26 日
clc
clear all
close all
a= input("Co-efficient of x^2: ");
b= input("Co-efficient of x: ");
c= input("Contant term: ");
d= b^2-4*a*c;
if a==0&&b==0;
disp ('The equation is invalid')
elseif a==0
x=-c/b;
disp('The equation is now linear and has one root',x);
end
fx=[a b c];
x=roots(fx);
if d>0
disp('The equation has two roots ', num2str(x(1)),',',num2str(x(2)));
elseif d==0
disp('The equation has one root ', num2str(x(1)));
else
disp('The equation has no real roots.');
end
Can you correct this code for me please.
ERROR MSG:
Co-efficient of x^2: 0
Co-efficient of x: 4
Contant term: -16
Error using disp
Too many input arguments.
Error in QUAD (line 12)
disp('The equation is now linear and has one root',x);
Shailendra Shankar
2023 年 4 月 26 日
Here are my requirements:
- need to show that if a=b=0, the equation is invalid
- if a=0, the equation is linear and the root is to be displayed
- if d>0, the equation has two roots which have to be displayed
- if d=0, the equation has only one root which has to be displayed
- if d<0, the equation has no real roots
Matt Kindig
2012 年 4 月 2 日
Well let's break down the question step by step, with the specified section of the documentation for each.
- Get input a, b, c from user
- Calculate discriminant D
- Compare D to 0.
- If D < 0, there will be imaginary roots. Since your assignment specifies real roots, throw an error here. If D == 0, there will be one root. If D > 0, there will be two roots.
- Calculate the roots using the quadratic formula.
- Display results to user or output (depending on assignment specification).
For step 1, look at the 'input' function in MATLAB. The rest of the assignment can be done using straightforward arithmetic operations (+,-,*,/). For steps 3-4, use an if-else structure.
This should get you started...
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