Double precision in mex file

1 回表示 (過去 30 日間)
Albert Pilos
Albert Pilos 2017 年 5 月 22 日
コメント済み: James Tursa 2017 年 5 月 22 日
Hi everyone,
I have a numerical model for some thermodynamical process. Its computations takes a long time and I found a possibility to do a mex file that sufficiently speeds up my problem. However, I obtain results that does not match with experimental results, however I am almost sure about good code implementation and a problem is grid-independent. Can the mex file reduce somehow precision of a variables?
Or another question. When i multiply two double-precise number is their multiplication also double-precision number?
Thx for any ideas

採用された回答

James Tursa
James Tursa 2017 年 5 月 22 日
編集済み: James Tursa 2017 年 5 月 22 日
Can the mex file reduce somehow precision of a variables?
No. Double precision in a mex routine is the same as double precision at the m-file level. You don't lose precision by doing the double precision calculation in a mex routine.
When i multiply two double-precise number is their multiplication also double-precision number?
Yes. The actual calculation may be done at higher precision, and then down-converted to double precision when stored. But it will not be done with less precision.
Both of those answers are related to the low level double precision calculations. But how the mex routine was written can certainly affect the final answer. So mex code that implements an algorithm differently from its m-file counterpart can certainly get a different answer even if both implementations are using double precision.
  4 件のコメント
Albert Pilos
Albert Pilos 2017 年 5 月 22 日
no just wrote "coder" into a command window and defined input variables
James Tursa
James Tursa 2017 年 5 月 22 日
How much different are the results?

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeOperators and Elementary Operations についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by