How to extract a certain part from a string?

Hi, I have a string variable with 9-digit value (not necessarily integer,could be capitalized-letter),

and I want to transform them into 8-digit value by removing the last digit value.

For example, my input will be some string as

 '0036R3879' '0034658A6'

and respectively they should be transformed into

'0036R387' '0034658A'

such that the last digit is removed and the output is still a sting with 8 digit.

I don't know how to operate with string in this case, and the function 'strrep' seems not to work here.

Can someone familiar with string operation help me out?

Thank you!

Answer 1

[Guillaume]

Assuming R2016b or later:

extractBefore(yourstringarray, 9)

[Star Strider]

According to the documentation, that syntax is new in R2017a.

[Guillaume]

Hum, no. My documentation says that it was introduced in R2016b. The behaviour was changed in R2017a to return the same data type as the first input whereas in R2016b, it always returned string arrays.

[Wei Feng Hsu]

It works! Thank you

Answer 2

[Image Analyst]

Try this:

myStrings = string({'0036R3879'; '0034658A6'; '00300658A6'});
% Print to command window:
t = table(myStrings)

for row = 1 : size(t, 1)
  % For every row...
  oldString = t.myStrings{row};
  t.myStrings{row} = oldString(1:end-1);
end
% Print to command window:
t

Hopefully it's rather self explanatory.