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why we need scale in implementations of FFT?

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Le Dung
Le Dung 2017 年 5 月 5 日
閉鎖済み: MATLAB Answer Bot 2021 年 8 月 20 日
Hi, Actually, i'm a civil engineering. I'm trying to understand on FFT because i need calculate response of structure under moving load in frequency domain after i calculated it (response) in time domain. And when i study on implementations of FFT in Matlab some problem that i don't understand. I found a document that provide to me a guide. I don't understand this sentence: "Since the FFT only does the summation of terms, the values returned by FFT must be scaled by dividing them by the number of points, k" with k is the number of points. i.e. 5th step in above figure. Why we need scale?

回答 (1 件)

Santhana Raj
Santhana Raj 2017 年 5 月 5 日
This is because the FFT equation implmented by Matlab is little different from your textbook equation.
Usually in a engineering textbook, you will see a (1/N) factor at the start of a DTFT/FFT equation. If you type "help fft" in your command window, you will be able to see that the forward fft formula is missing the (1/N) factor.

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