Higher derivatives in "PDEPE"
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When I want to consider "PDEPE" command for 1D PDE like Du/Dt = \nabla^4 u = \nabla \cdot \nabla^3 u, how can express the higher derivatives in f?
That is, f = \nabla^3 u. How can I modify this term with DuDx?
Thanks in advance.
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David Ding
2017 年 4 月 27 日
HI Jaesung,
The "pdepe" function is suited to solve the PDE of the form shown in equation (1-3) of:
In your case, "f = \nabla^3 u" is unfortunately not in this form. MATLAB does offer ways to solve these kinds of PDEs numerically, for example, via the "pdeval" function.
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Jaesung Lee
2017 年 4 月 30 日
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Bill Greene
2017 年 4 月 30 日
Your equation for f_1 shows a derivative wrt y for u_2. I assume that is simply a typographical error? If that is the case, these equations look to me to be in a form acceptable to pdepe. What problem did you run into when you tried to solve them?
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