It only shows the else value if value of b crosses 15 even once.

b =  AXIS(1:100,1) - KOTAK(1:100,1);

avg5 = zeros(5,1);
for k = 5:length(b)
    avg5(k) = mean(b(k-4:k,1));
end
a = 0;
avg5 = [a;avg5];
avg5(numel(avg5),:) = [];

std5 = zeros(5,1);
for al = 5:length(b)
    std5(al) = std(b(al-4:al,1));
end
% a = 0;
std5 = [a;std5];
std5(numel(std5),:) = [];

up5 = zeros(length(std5),1);

for d = 1 : length(std5)
    if abs(b) < 14.5
       up5(d) =  std5*2 + avg5;
     down5(d) = std5*(-2) + avg5;
    else
       up5(d) =  std5*2 + avg5;
     down5(d) = std5*(-2) + avg5;
    end
end

It works well till up5 = zeros(length(std5,1));

[Ganesh Hegade]

You are trying to say that the variable 'up5' is not storing values when abs(b) < 15 ?

[Geoff Hayes]

Adhish - how is b set? Please post more of your code.

[Adhish Aggarwal]

I have mine given my full code p above. Please let me know. Thank you

Answer 1

[Steven Lord]

That's the correct behavior. From the documentation for the if keyword: " if expression, statements, end evaluates an expression, and executes a group of statements when the expression is true. An expression is true when its result is nonempty and contains only nonzero elements (logical or real numeric). Otherwise, the expression is false. "

In your case, you probably want to use logical indexing instead.

[Adhish Aggarwal]

I have mine given my full code p above. Please let me know. Thank you