How to replace the diagonal elements of a matrix with 0 fro avoiding self loops?
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I have a matrix
M= 1 0 0 0 1 0
0 1 0 1 0 0
0 0 1 0 1 1
1 0 0 1 0 0
1 1 1 0 0 0
0 0 0 1 0 1
I want to replace all the diagonal elements in this matrix to 0 if it is 1.
1 件のコメント
Ramtin Nazerian
2022 年 12 月 21 日
Out = M.*-(eye(height(M))-1);
This will make all the diagonal values of your matrix zero as long as the matrix is square. hope that helps :).
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Stephen23
2017 年 4 月 19 日
編集済み: Stephen23
2017 年 4 月 19 日
Method one: indexing:
M(1:1+size(M,1):end) = 0
Method two: eye:
M.*~eye(size(M))
1 件のコメント
Stephen23
2017 年 4 月 19 日
A strict interpretation of the question requires only diagonals equal to one get changed to zero: this is easy to implement with eye:
M.*~(eye(size(M)) & M==1)
Roger Stafford
2017 年 4 月 19 日
If your matrix M is not square and if you only want those diagonal elements changed to zero “if it is 1”, then you can do the following. Other diagonal elements not equal to one will remain unchanged. (Your description was perhaps a little ambiguous on this latter point.)
[m,n] = size(M);
d = 1:m+1:min(m^2,m*(n-1)+m);
f = find(M(d))==1;
M(d(f)) = 0;
4 件のコメント
Zeina Abdullah
2022 年 1 月 5 日
@Stephen can you help me by try to answer the last question in my profile please
Christine Tobler
2017 年 5 月 23 日
編集済み: Christine Tobler
2017 年 5 月 23 日
If you are using the graph/digraph classes, you can also tell the constructor not to insert any self-loops for the diagonal elements:
g = graph(A, 'omitSelfLoops');
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