waterfall plot show error

2 ビュー (過去 30 日間)
Raady
Raady 2017 年 4 月 15 日
回答済み: Star Strider 2017 年 4 月 15 日
I have three signals of 4096 time amplitudes in each.
signal1 = channel1(1:4096);
signal2 = channel2(1:4096);
signal3 = channel3(1:4096);
figure(1);
% waterfall(signal1',signal2',signal3');
waterfall(signal1,signal2,signal3);
it says
Error using horzcat
Dimensions of matrices being concatenated are not consistent.
but my signal is of same duration(length). How plot it ? I want to compare the amplitudes of the signals in waterfall plot rather than subplots. Do I need to input any other things for the plot ?

回答 (1 件)

Star Strider
Star Strider 2017 年 4 月 15 日
Try this:
channel1 = sin(pi*[1:4096]/1024); % Create Data
channel2 = cos(pi*[1:4096]/1024); % Create Data
channel3 = sin(pi*[1:4096]/1024).*cos(pi*[1:4096]/2048); % Create Data
signal1 = channel1(1:4096);
signal2 = channel2(1:4096);
signal3 = channel3(1:4096);
figure(1);
% waterfall(signal1',signal2',signal3');
waterfall([signal1; signal2; signal3]); % Concatenate Vectors Into A Matrix

カテゴリ

Help Center および File ExchangePropagation and Channel Models についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!