peak width calculation methods
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Hi
I'm calculating peak width using half-prominence method . For the peak in the rectangle is there is a method to make the horizontal line the finds the widths to shift up or make vertical line like this image
? . I tried both methods for peak width detection (half-width, half-prominence ) but it gave me the same results .
Half-prominence
close all
order =9 ;
framelen =15;
lx = 20;
% generate sinal
x = 1:1:1432;
y = (AV)';
y = sgolayfilt(y,order,framelen);
% get derivatives
dy = diff(y);
dx = diff(x);
dy_dx = [0 dy./dx];
findpeaks(y,x,'Annotate','extents','MinPeakProminence',0.006);
% get peaks with width computed by 'findpeaks'
[pks,locs,peakWidth1,p] = findpeaks(y,x,'MinPeakProminence',0.006);
half-height :
order =7 ;
framelen =11;
x=-AV;
lx = 20;
sgf = sgolayfilt(x,order,framelen);
hold on;
sgf= 0.02-sgf;
findpeaks(sgf,'MinPeakProminence',0.004,'WidthReference','halfheight','Annotate','extents');
[pks,locs,widths,proms]=findpeaks(sgf,'MinPeakProminence',0.004,'WidthReference','halfheight');
pks = -pks;
plot(locs,pks,'g*');
text(locs+.02,pks,num2str((1:numel(pks))'));
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採用された回答
Greg Dionne
2017 年 4 月 14 日
It seems you are interested in the relative height of the spike with its immediate vicinity (not with respect to higher peaks). To do that, try subtracting off the results of a lowpass or median filter first.
findpeaks(sgf - medfilt1(sgf,21), ...)
その他の回答 (2 件)
sarmad m
2017 年 4 月 27 日
編集済み: sarmad m
2017 年 4 月 27 日
1 件のコメント
Greg Dionne
2017 年 4 月 27 日
looks like you forgot the medfilt1 in the second call to findpeaks.
You may also try using 'WidthReference' 'halfheight' if you're after FWHM values once you've removed the baseline.
load data.csv
close all
% plot default annotated peaks
order =11 ;
framelen =15;
% generate sinal
y = -(data)';
y = sgolayfilt(y,order,framelen);
%plot(x);
findpeaks(y - medfilt1(y,50),'Annotate','extents','MinPeakProminence',0.003);
% get peaks with width computed by 'findpeaks'
[pks,locs,peakWidth1,p] = findpeaks(y - medfilt1(y,50),'MinPeakProminence',0.003);
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