Find an element in a matrix

Hello,

So, my problem is : I have a matrix let's call it A :

     0     1     0     0
A =  0     0     1     0
     0     0     0     0
     1     0     1     0

I want to find the rows and cols of all the "1" in A, I used find and got :

 [rows cols] = find (A == 1) 
 rows = 4 1 2 4     and        cols = 1 2 3 3

now that's not what I want, as the search in A goes "top to bottom, left to right" and I want it to be "left to right, top to bottom", so the result should be something like this :

   rows = 1 2 4 4     and    cols = 2 3 1 3

Any ideas ?

Thanks.

Answer 1

[Andrei Bobrov]

 [cols rows] = find (A.' == 1)

Answer 2

[Adam]

[cols, rows] = find( A' == 1 )

Answer 3

[Abdel A]

You my friend is a genius. I did think of the matrix transpose but didn't think of reversing cols and rows. Thanks.