any single vector element =0 than loop again rotate and again loop start from first line

30 element in vector check each value of vector and any element in vector =0 than loop again start from first step i want to go at first line of code if condition not satisfy , this vector is get after some process if any content is not zero than move forward and if any content is zero than again loop rotate

[Pratik Anandpara]

code is so longer so i not post here

Answer 1

[Jan]

I'm not sure, if I understand the question correctly. A guess:

ready = false;
while ~ready
  ... your code
  v = randi([-10, 10], 1, 30);  % Pseudo-data, use your vector instead
  if all(v)  % Stop loop if v does not contain any 0
    ready = true;
  end
end

[Pratik Anandpara]

if v is matrix of 30*2 than which modification needed

[Jan]

You might need e.g. all(v(:)) to consider all elements.