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Convert formula into coding form

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Syakira Akmal
Syakira Akmal 2017 年 4 月 1 日
回答済み: Image Analyst 2017 年 4 月 1 日
Hi, i don't know how to convert formula into coding form. Example of formula
theta(kx, ky) = arctan(dy/dx)

回答 (3 件)

Star Strider
Star Strider 2017 年 4 月 1 日
The arguments to the function do not match the arguments to the arctangent function. Are ‘kx’ and ‘ky’ the same as ‘dx’ and ‘dy’ or different?
One of these should do what you want:
theta = @(kx, ky) atan2(ky,kx); % The Values (Or Vectors) Themselves
theta = @(kx, ky) atan2(gradient(ky),gradient(kx)); % The Derivatives Of The Vectors
The atan2 function puts the returned angles in the correct quadrants. The atan function does not.
  2 件のコメント
Syakira Akmal
Syakira Akmal 2017 年 4 月 1 日
(kx, ky) is a point. dy = In(kx,ky+1) - In(kx,ky-1) dx = In(kx+1,ky) - In(kx-1,ky)
Star Strider
Star Strider 2017 年 4 月 1 日
My function then changes to:
theta = @(kx, ky) atan2(In(kx,ky+1) - In(kx,ky-1), In(kx+1,ky) - In(kx-1,ky)); % Directly Using ‘In’
That should work.

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John D'Errico
John D'Errico 2017 年 4 月 1 日
編集済み: John D'Errico 2017 年 4 月 1 日
I'd strongly suggest that you start reading the getting started tutorials. This is a very basic question, although I honestly have no idea what it is that you really want to do here. If I had to guess, you need to learn how to write a function.
Using a four quadrant atan, this would do what you want.
theta = @(kx,ky) = atan2(ky,kx);
Or do this:
theta = @(kx,ky) = atan(ky/kx);

Image Analyst
Image Analyst 2017 年 4 月 1 日

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