Inverse of 3D array with zeros

1 回表示 (過去 30 日間)
Burak
Burak 2017 年 3 月 30 日
コメント済み: Walter Roberson 2017 年 3 月 31 日
Hi everyone , I need to calculate inverse of A(v,n,m+N+1) for 3rd dimension , I mean array B, but there are zeros here and I can't calculate inverse for all m because matrix is singular.Here is the code;
for m=-N:N
if m==0
k=1;
else
k=abs(m);
end
for v=k:N
for n=k:N
A(v,n,m+N+1)=(v+n)*m;
end
end
end
for i=1:2*N+1
B(:,:,i)=inv(A(:,:,i);
end
I need help, If anyone can help me , appreciated. Thanks for your concern.
  1 件のコメント
Walter Roberson
Walter Roberson 2017 年 3 月 31 日
What output are you hoping for in the situation where the array is singular?

サインインしてコメントする。

回答 (0 件)

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by