Inverse of 3D array with zeros

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Burak
Burak 2017 年 3 月 30 日
コメント済み: Walter Roberson 2017 年 3 月 31 日
Hi everyone , I need to calculate inverse of A(v,n,m+N+1) for 3rd dimension , I mean array B, but there are zeros here and I can't calculate inverse for all m because matrix is singular.Here is the code;
for m=-N:N
if m==0
k=1;
else
k=abs(m);
end
for v=k:N
for n=k:N
A(v,n,m+N+1)=(v+n)*m;
end
end
end
for i=1:2*N+1
B(:,:,i)=inv(A(:,:,i);
end
I need help, If anyone can help me , appreciated. Thanks for your concern.
  1 件のコメント
Walter Roberson
Walter Roberson 2017 年 3 月 31 日
What output are you hoping for in the situation where the array is singular?

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