Find the closest match values in cell array
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Hi guys, I got a cell array and I want to find the index of the array that closest match my defined values. Here is my cell array:
A =
[565.11,579.965]
[567.016,581.921]
[574.162,589.256]
575.909
[568.804,583.373]
[570.197,584.803]
[566.005,576.676,587.758]
As you can see the length of each row is not the same, that's why I couldn't put it in the form of a normal array. So, if I want to find the index that is the closest match 567.5 and 586.5. How can I do that?
Thanks!
0 件のコメント
回答 (2 件)
the cyclist
2017 年 3 月 10 日
Here's one way:
A = {
[565.11,579.965]
[567.016,581.921]
[574.162,589.256]
575.909
[568.804,583.373]
[570.197,584.803]
[566.005,576.676,587.758]};
val = 567.5;
[~,indexToClosestMatch] = min(cellfun(@(x)min(abs(x-val)),A));
3 件のコメント
Image Analyst
2017 年 3 月 10 日
So what's wrong with just doing it twice???
val = 567.5;
[~,indexToClosestMatch1] = min(cellfun(@(x)min(abs(x-val)),A));
val = 586.5;
[~,indexToClosestMatch2] = min(cellfun(@(x)min(abs(x-val)),A));
Star Strider
2017 年 3 月 10 日
‘How can I do that?’
One approach:
A = {[565.11,579.965]
[567.016,581.921]
[574.162,589.256]
575.909
[568.804,583.373]
[570.197,584.803]
[566.005,576.676,587.758]};
v = [567.5 586.5];
sz = cellfun(@(x)size(x,2), A, 'Uni',0); % Calculate Sizes Of Vectors
A_idx = cellfun(@(x)eq(x,2), sz, 'Uni',0); % Select Only Elements Of ‘A’ With 2 Columns
A_sel = A(cell2mat(A_idx)); % Elements Of ‘A’ Meeting Criteria
D = pdist2(v,cell2mat(A_sel)); % Distance Between ‘v’ And Elements Of ‘A’
[~,MinIdx] = min(D); % Indes OF Minimum Distance
A_closest = A_sel{MinIdx} % Element Values Of Minimum Distance
A_closest =
570.2 584.8
5 件のコメント
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