how do I remove rows with duplicated values?

let say i have matrix A
A = [1 2 3 4 5;
3 5 7 9 11;
1 1 4 5 7;
3 5 6 6 9;
1 4 10 15 16]
and wanted to remove all rows with values that repeated with each other. Then A will become
A = [1 2 3 4 5;
3 5 7 9 11;
1 4 10 15 16]
Thanks for the help in Advance

 採用された回答

the cyclist
the cyclist 2017 年 3 月 7 日
編集済み: the cyclist 2017 年 3 月 7 日

4 投票

Here is a one-liner:
A(any(diff(sort(A,2),[],2)==0,2),:)=[];
If you are certain that each row is already in numerical order (as in your example), you can skip the sorting step.
The algorithm is the following:
  • Use sort to sort the values in each row
  • Use diff to get the difference between consecutive values in each row
  • Use any to check if any of those differences equal zero (indicating a duplicate values)
  • Use the output of the any command, which is a logical index, to delete the rows that have duplicates

3 件のコメント

jesus escareno
jesus escareno 2017 年 3 月 9 日
Thanks yea it was already sort it out. So i only needed diff and any.
Srinivas Kolluru
Srinivas Kolluru 2020 年 8 月 15 日
Works perfectly. Thank you
Otto Liljansalo
Otto Liljansalo 2024 年 3 月 14 日
Nice programming there!

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