フィルターのクリア

Remove rows of zeroes, and extract the removed rows indices

1 回表示 (過去 30 日間)
czeslaw
czeslaw 2017 年 3 月 4 日
コメント済み: Star Strider 2017 年 3 月 4 日
Hi all,
I have T =
0 0 0 0
1 2 0 4
5 6 0 8
0 0 0 0
10 11 0 12
t2=T(any(T,2),:) will give
t2 =
1 2 0 4
5 6 0 8
10 11 0 12
But how can I efficiently retrieve the indices of the removed rows from T, that is: 1,4 ?? Then how can I efficiently retrieve the indices of the not removed rows from T, that is: 2,3,5 ?? Without using while, for loop etc.
Thank you in advance.

採用された回答

Star Strider
Star Strider 2017 年 3 月 4 日
編集済み: Star Strider 2017 年 3 月 4 日
This works:
T = [0 0 0 0
1 2 0 4
5 6 0 8
0 0 0 0
10 11 0 12];
RemovedRows = all(T == 0, 2)
RemovedRowsIdx = find(RemovedRows)
KeptRowsIdx = find(any(T,2))
RemovedRows =
5×1 logical array
1
0
0
1
0
RemovedRowsIdx =
1
4
KeptRowsIdx =
2
3
5
EDIT Remembered ‘KeptRowsIdx’.
  4 件のコメント
Image Analyst
Image Analyst 2017 年 3 月 4 日
If speed is what was needed, you shouldn't even use find() at all. I doubt he really needed the actual row numbers - that's why I didn't even bother to compute them. I think it's just the final matrix that is wanted. He'll probably never even use the row numbers again - so use logical indexing, which you already have, rather than doing the additional step to get linear indexing.
Star Strider
Star Strider 2017 年 3 月 4 日
@Image Analyst —
Possibly, but that wasn’t the impression I got.
Quoting:
  • ‘But how can I efficiently retrieve the indices of the removed rows from T, that is: 1,4 ??Then how can I efficiently retrieve the indices of the not removed rows from T, that is: 2,3,5 ??’
The index numbers appear to be requested.

サインインしてコメントする。

その他の回答 (1 件)

Image Analyst
Image Analyst 2017 年 3 月 4 日
Try this:
rowsToKeep = ~all(T == 0, 2)
t2 = T(rowsToKeep, :)

カテゴリ

Help Center および File ExchangeResizing and Reshaping Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by