i am writting a code for Vigenere Cipher but i am troubled with a question that how could i repeat key as that of my text to be ciphered

my code is given below but error is key length is not same as plain_text

% Matlab code to encipher and Decipher Vigenere Cipher
% input parameter

key = input('Enter the cipher key:  ','s' );
plain_text =input('ENter the text to be ciphered: ','s');
length(plain_text)

k=repmat((key),1,length(plain_text))
%k1=k(:)'
%k=repelem(key,length(plain_text))
% Vigenere ciphere Encryption

plain_num=plain_text-97;
k1=k-97;
ciphered_num=rem(plain_num+k1,26);
ciphered_text=char(ciphered_num+97)

% Vigenere ciphere Decryption

ciphered_num=ciphered_text-97;
deciphered_num=rem(ciphered_num-k1,26);
deciphered_text=char(deciphered_num+97)

Answer 1

[Geoff Hayes]

mahnoor - the problem is with

 k=repmat((key),1,length(plain_text))

You don't want to repeat the key for each letter of plain_text (unless the key is a single character) but you want to repeat it enough times so that the "extended" key has the same characters as the plain text. For example, if

 key = 'logan';
 plainText = 'superheromovies2017';

then the extended key would be

 extendedKey = 'loganloganloganloga';

So your code will have to determine this. I suppose you could do something like

 extendedKey = '';
 if length(key) < length(plainText)
     keyReps = floor(length(plainText)/length(key));
     extendedKey = [repmat(key,1,keyReps) key(1:rem(length(plainText),length(key)))];
 else
     extendedKey = key(1:length(plainText));
 end

This should give you the correct key, but you may want to step through the remainder of the code to ensure that it is doing what you expect.

[mahnoor khalid]

thanks it works

[mohamad gholami]

i have a problem in this code about key . please help me . [e-mail]

[maxua ua]

i have a problem in this code. please help me . [e-mail]