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Run a for loop for three different types of excitation

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Tom
Tom 2012 年 3 月 19 日
I need to run a for loop for three different scenarios. I tried this: -
etyp = 3 %number of excitation types
for i = 1:etyp
if i = 1
excitation = 'noise';
end
if (i = 2)
excitation = 'mls';
end
if (i = 3)
excitation = 'sweptsine';
end
end
but I get an error that I don't understand. Could anyone explain what's wrong with this code? Thanks
  1 件のコメント
Matt Fig
Matt Fig 2012 年 11 月 2 日
Tom's question
I need to run a for loop for three different scenarios. I tried this: -
etyp = 3 %number of excitation types
for i = 1:etyp
if i = 1
excitation = 'noise';
end
if (i = 2)
excitation = 'mls';
end
if (i = 3)
excitation = 'sweptsine';
end
end
but I get an error that I don't understand. Could anyone explain what's wrong with this code? Thanks

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採用された回答

Tom
Tom 2012 年 3 月 19 日
worked it out
equals signs for the ifs need to be doubles i.e. ==

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