Can anyone explain the code I have given for visual cryptography?

This is the main program:

clc;
clear all;
close all;
tic;
%Input
inImg = imread('D:\our project\crypt\lena.bmp');
inImg=im2double(imresize(inImg,0.5));
figure
imshow(inImg);
inImg=im2bw(inImg);
%inImg=double(inImg);
figure
imshow(inImg);
title('Secret Image');

%fn call
[share1, share2, share12] = VisCrypt(inImg);
toc;
%Output
share1 = imresize(share1, [256 256]);
%share1=im2double(imresize(share1,0.5,'nearest'));
figure
imshow(share1);
title('Share 1');
share2 = imresize(share2, [256 256]);
figure
imshow(share2);
title('Share 2');
share12 = imresize(share12, [256 256]);

figure;imshow(share12);title('Overlapping Share 1 & 2');
imwrite(share1,'Share1.jpg');
imwrite(share2,'Share2.jpg');
imwrite(share12,'Overlapped.jpg');

This function is to generate shares:

function out = generateShare(a,b)

a1 = a(1);
a2 = a(2);
b1 = b(1);
b2 = b(2);

in = [a
      b];
out = zeros(size(in));
randNumber = floor(1.9*rand(1));

if (randNumber == 0)
    out = in;
elseif (randNumber == 1)
    a(1) = a2;
    a(2) = a1;
    b(1) = b2;
    b(2) = b1;
    out = [a
           b];   
end

This function generates the splitting of black and white pixel:

function [share1, share2, share12] = VisCrypt(inImg)

s = size(inImg);
share1 = zeros(s(1), (2 * s(2)));
share2 = zeros(s(1), (2 * s(2)));

%%White Pixel 

s1a=[1 0];
s1b=[1 0];
[x y] = find(inImg == 1);
len = length(x);

for i=1:len
    a=x(i);b=y(i);
    pixShare=generateShare(s1a,s1b);
    share1((a),(2*b-1):(2*b))=pixShare(1,1:2);
    share2((a),(2*b-1):(2*b))=pixShare(2,1:2);
end

%Black pixel

s0a=[1 0];
s0b=[0 1];
[x y] = find(inImg == 0);
len = length(x);

for i=1:len
    a=x(i);b=y(i);
    pixShare=generateShare(s0a,s0b);
    share1((a),(2*b-1):(2*b))=pixShare(1,1:2);
    share2((a),(2*b-1):(2*b))=pixShare(2,1:2);
end

share12=bitor(share1, share2);

   share12= ~share12;

[Walter Roberson]

Possibly Yes, but surely documenting the code you wrote is your responsibility?? You would be the person who knows the code the best.

If you are copying someone's code, then it would be easier for the author to explain it than for any of us to explain it.