How to solve an ODE with an array using ODE45?

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DIP
DIP 2017 年 2 月 20 日
コメント済み: DIP 2017 年 3 月 6 日
I have an ODE, udY/dx=S , where Y and S are arrays , how do I solve it using ODE45 ???
  3 件のコメント
DIP
DIP 2017 年 2 月 20 日
編集済み: DIP 2017 年 2 月 20 日
velocity. its constant
Jan
Jan 2017 年 2 月 20 日
@DIP: Please provide more details. "velocity" does not help, because Matlab does not care about the physical meaning of variables. Post the function you want to integrate, preferrably in valid Matlab code. If it is written correctly, all you have to do is calling ode45.

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DIP
DIP 2017 年 3 月 6 日
% Solution 4: Chemical Species Concentration as a Function of Axial Distance
clc
clear
% Constants
L = 0.12;
N = 39;
T(1:N) = 750;
delx = L/(N-1);
xspan = 0:delx:0.12;
C0 = [0.52 0.99 0.0];
% ODE 45 Code
[x,C]=ode45('hw2_4',xspan,C0);
% Plots
subplot(2,1,1);
plot(x,C(:,1),'b--o',x,C(:,2),'g--+',x,C(:,3),'r--s')
legend('C_{CO}','C_{O2}','C_{CO2}')
xlabel('Axial (x) Direction [m]')
ylabel('Concentrations [mol/m^3]')
title('Molar Concentration vs Distance')
Function File:
function dcdx=hw2_4(x,C)
% Constants
u = 1.5;
A = 2.2e10;
Ea = 130000;
Ru = 8.3145;
T = 750;
% Rate Constants
R(1) = -A * (exp(-Ea / (Ru*T))) * C(1) * sqrt(C(2));
R(2) = 0.5 * R(1);
R(3) = -R(1);
dcdx = [R(1);R(2);R(3)]/u;
  1 件のコメント
DIP
DIP 2017 年 3 月 6 日
Thank you Jan, Star Strider,

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その他の回答 (2 件)

Jan
Jan 2017 年 2 月 20 日
編集済み: Jan 2017 年 2 月 21 日
ode45 works with vectors, therefor if Y is a vector, the provided examples in the docs should help: https://www.mathworks.com/help/matlab/ref/ode45.html#examples . If not, please post more details by editing the question.
[EDITED, Considering your comments] Perhaps you mean this:
function main
% Initial Conditions
Cco(1) = 0.52; %Y1
Co2(1) = 0.99; %Y2
Ch2o(1) = 0; %Y3
L = 0.12;
N = 39;
delx = L/(N-1);
x = 0:delx:0.12;
C0 = [Cco; Co2; Ch2o];
[x,C] = ode45(@DiffEQ, x, C0);
plot (x,C)
end
function dC = DiffEQ(x, C)
u = 1.5;
A = 2.2e10;
Ea = 130;
Ru = 8.3145;
T = 750;
Cco = C(1);
Co2 = C(2);
Ch2o = C(3);
Rco = -A * (exp(-Ea / (Ru*T))) * Cco * sqrt(Co2); %S1
Ro2 = 0.5 * Rco; %S2
Rh2o = -Rco; %S3
dC = [Rco; Ro2; Rh2o] / u;
end
This needs a lot of processing time. Using ode15s was successful in less than a second (are you sure the system is not stiff). The diagram looks nicer, if you define:
x = [0, 0.12];
  10 件のコメント
DIP
DIP 2017 年 2 月 21 日
I think its got to do with defining the arrays of C and R correctly.
Jan
Jan 2017 年 2 月 21 日
@DIP: @(x,C) R/u is constant. Changes in the coordinates are not considered, because all calls of "R/u" reply the same value. Better use a normal function instead of a anonymous function. I've showed you already, how to do this.
Concerning:
documentation for the last line of your main function
do you mean "plot(x,C)"?

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Star Strider
Star Strider 2017 年 2 月 20 日
See if the approach in Monod kinetics and curve fitting will do what you want.
You will have to adapt it to your data and differential equations. The essential design should work.

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