フィルターのクリア

Finding location of change of signs of a matrix's elements

19 ビュー (過去 30 日間)
Volkan Yangin
Volkan Yangin 2017 年 2 月 18 日
コメント済み: MA-Winlab 2019 年 4 月 7 日
Hi everbody, I have a matrix like this:
A=[0 0 0 0.33 0.33 0.33 0 0 0 -0.33 -0.33 -0.33 0 0 0];
How can i find location of change of signs? I get an error while using find and diff command. I think, i have made a mistake because of the < and > symbols. May you help me? Thanks.

採用された回答

Walter Roberson
Walter Roberson 2017 年 2 月 18 日
find(diff(sign(A)))+1
to return the locations of the beginning of the new sign.
Note that this includes changing to 0, as 0 has a different sign than positive numbers or negative numbers.
  3 件のコメント
MA-Winlab
MA-Winlab 2019 年 4 月 6 日
@Roberson, I tried your approach for finding the locations of change from 0 to 1 and from 1 to 0, but they are in one array.
So, if I have this array and want to find the locations of change from 1 to 0 (returned in an array) and the locations of change from 1 to 0 (returned in a SEPRATE array), how can I modify this line?
Thank you
A=[0 0 0 1 1 1 0 0 0 1 1 1 0 0 0];
MA-Winlab
MA-Winlab 2019 年 4 月 7 日
Update
I figured out how to do that (in my case, the vector of 0s and 1s has an even number):
OpenClose = find(diff(sign(A))) + 1;
OneToZero = OpenClose(1:2:end)
ZeroToOne = OpenClose(2:2:end)

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by