In the Python API, how can I redirect the output of an asynchronous function call of a function without return value?
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I am using the Python API and I want to redirect the output of an asynchronously called function without return value. Is this maybe impossible?
My Python Script looks a little bit like this:
import matlab.engine as eng
import StringIO
out = StringIO.StringIO()
MAT = eng.start_matlab()
ret = MAT.func('arg', async=True, nargout=0, stdout=out)
while not ret.done() : pass
print out.getvalue()
MAT.quit()
When running this script, there is only a line feed / carriage return printed. The return value of
ret.result()
is "None".
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採用された回答
Bo Li
2017 年 2 月 16 日
What about adding "ret.result()" before printing the output buffer like following?
while not ret.done() : pass
ret.result()
print out.getvalue()
3 件のコメント
Esteban Henriques
2018 年 5 月 11 日
編集済み: Esteban Henriques
2018 年 5 月 11 日
From:
def result(self, timeout=None):
in fevalfuture.py, it seems that it is not possible to get any feedback from the out stream until the call is done. Doesn't this at least in part defeat the purpose of an async call?
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