How to cut audio file into segments?
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I have an audio file (.wav) which I need to cut into segments. Segments (start and stop values) are stored in cell array C. I managed to get values only from one cell to cut the sound file, but I don't know how to get one by one values from cell array C and parallel cut the sound signal. Intervals in the text file look like this:
0.300000 0.410000 ,0.41000 0.430000 ,0.95000 0.990000 ,1.21500 1.260000 ,...
In cell array C every interval is in it's own cell -
'0.300000 0.410000', '0.41000 0.430000' , ...
I have this code:
[data,Fs] = audioread('sound.wav');
list = fopen('intervals.txt','r');
for k=1:length(list)
content = fgets(list)
C= strsplit(content,',')% splits str at the delimiters specified by delimiter
nums = C{1,k} % gets only data from the first cell
x = str2num(nums) %convert from char to numeric value
for n=1:length(x)
start=x(1)
stop=x(2)
N = length(data);
totaldur = N/Fs; % total duration
t = linspace(0,totaldur,N); % create a time vector
%logical indexing
seg1 = data(t>start & t<stop)
sound(seg1) %play the segment
end
end
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回答 (1 件)
Rahul
2025 年 1 月 3 日
As per the code shared, in order to apprpriately cut the audio signal into segments as per the specified list of intervals, consider indexing the data in the following way:
[data, Fs] = audioread('sound.wav');
list = {'0.300000 0.410000', '0.41000 0.430000' , ...}
for k = 1:length(list)
interval = list{k};
x = str2num(interval);
if length(x) == 2
start = x(1);
stop = x(2);
startIdx = max(1, floor(start * Fs));
stopIdx = min(length(data), ceil(stop * Fs));
segment = data(startIdx:stopIdx); % Indexing appropriately taking Fs(Sampling frequency) into account
sound(segment, Fs); % Fs(Sampling frequency) helps in obtaining the correct aound output.
end
end
The following MATLAB Answer and Mathworks documentations can be referred to know more:
'Signal Labeller': https://www.mathworks.com/help/signal/ref/signallabeler-app.html
Hope this helps! Thanks.
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