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How to delete rows that contain NaN in a table

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012786534
012786534 2017 年 2 月 3 日
コメント済み: dpb 2017 年 6 月 12 日
Hello all,
So how do you delete all the rows that contain NaNs in a table (not a matrix or a cell array)? I have tried various versions of
tableA(~any(~isnan(tableA), 2),:)=[];
but none work.
Thank you
  1 件のコメント
Image Analyst
Image Analyst 2017 年 2 月 3 日
Make it easy for us to help you by suppling code to generate a table with nans in it. Then I can try some things. And do any of your columns contain anything other than numbers? Like strings or something?

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採用された回答

dpb
dpb 2017 年 2 月 3 日
編集済み: dpb 2017 年 6 月 12 日
If the table uses default missing values for the various types (see documentation for the various types; NaN is for numeric) then
tableA=tableA(~any(ismissing(tableA),2),:);
should do the trick. This will eliminate other variables that are missing besides numeric, too, of course, leaving only a complete table.
  2 件のコメント
sensation
sensation 2017 年 6 月 12 日
Hi,
I have tried this but got an error: Error using any Not enough input arguments.
I have first column as string and second is numeric with nan values sometimes inside. I want to get riw of those rows with nans.
thank you
dpb
dpb 2017 年 6 月 12 日
Missing parens... ismissing(tableA) returns 2D logical, need any applied to it in 2d dimension to return the rows with missing value, then keep the complement.

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その他の回答 (1 件)

Peter Perkins
Peter Perkins 2017 年 2 月 6 日
If you have access to R2016b, you can use rmmissing .

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