How can I write such an equation on Matlab?
3 ビュー (過去 30 日間)
表示 古いコメント
Hello everyone,
I need to know how to write such an equation on Matlab, and define what is x(t) before computing it:

Furthermore, how can I get the distribution of x(50), plot its histogram and compute its standard deviation?
Thank you in advance.
採用された回答
Niels
2017 年 2 月 1 日
編集済み: Niels
2017 年 2 月 1 日
i am not implementing your homework, i am just put the code in the right order so that it looks like you wanted it to do in the way your showed me so far. To me it still looks like this code probably isnt the monte carlo simulation, but that might be your homework to figure out how it works.
function [x_t] = x(t) % you call the function with x(anyvalue) to get x_t
% if you saved it as x.m in the current folder
% define the number of simulations
Nsim= 10000; %%====== is unused
% extract values from epsilon
% epsilon is distributed as a standard normal
N = 10000; %======= shouldnt be this the same as your n /or x?
u=unifrnd(0,1,N,1);
epsilon=norminv(u,0,1);
%define the variables
% n=25; % not needed anymore
% x_t=0;
x_t1=0; % x_t-1
x_t2=1; % x_t-2
for i=1:t
x_t = x_t1 -0.01* x_t2 + 0.1* x_t1* epsilon(i);
x_t2 = x_t1;
x_t1 = x_t;
end
end
type
x(50)
in your command window to get x_50
0 件のコメント
その他の回答 (2 件)
Niels
2017 年 2 月 1 日
編集済み: Niels
2017 年 2 月 1 日
In general you would write a recursiv function
function result=rekursiv(xn)
if xn==-1
result=missingInYourCode;
elseif xn==0
result=1;
else
result=rekursiv(xn-1)- 0.01* rekursiv(xn-2)...;
end
end
When rekursiv(1) is called there the value of x_-1 is needed. No x_-1 => no solution
Roger Stafford
2017 年 2 月 2 日
編集済み: Roger Stafford
2017 年 2 月 2 日
Recursion is not a good idea on an iteration of this sort where at each step two different earlier levels are consulted. At the first step there must be two recursive calls. At the second step there must be two calls, each of which requires two calls. As you progress along the iteration, the number of calls expands exponentially. This is of course a great waste because there will be recursive calls made repeatedly for the same value of i.
It is much, much better to do the iteration with a for-loop or while-loop:
for i = 2:50
x(i) = x(i-1)*(1+0.1*e(t(i)))-0.01*x(i-2);
end
Note: you haven’t told us what e(t) is. Is this where the stochastic property comes in? If so, you would have the repeat the above loop a great many times to simulate this stochastic behavior accurately.
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!