how to add 3 matrices with one dimension same for all and other dimension different?
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If I have
A=[1;
2;
3]
B=[2 3 4;
5 6 7;
8 9 0]
C=[3 4 5 6;
9 8 7 6;
5 4 2 1]
all 3 matrices have 3 rows but columns different. I want to add elements of rows of all matrices in this way for example I want
D=[(1+2+3) (1+2+4) (1+2+5) (1+2+6) (1+3+3) (1+3+4) (1+3+5) (1+3+6) (1+4+3) (1+4+4) (1+4+5) (1+4+6);
(2+5+9) (2+5+8) (2+5+7) (2+5+6) (2+6+9) (2+6+8) (2+6+7) (2+6+6) (2+7+9) (2+7+8) (2+7+7) (2+7+6);
(3+8+5) (3+8+4) (3+8+2) (3+8+1) (3+9+5) (3+9+4) (3+9+2) (3+9+1) (3+0+5) (3+0+4) (3+0+2) (3+0+1)]
2 件のコメント
John Chilleri
2017 年 1 月 24 日
Do you need this generalized to any size matrix, or will it strictly be with three matrices of these exact sizes?
採用された回答
Niels
2017 年 1 月 24 日
編集済み: Niels
2017 年 1 月 24 日
[rows,col_B]=size(B);
[~,col_C]=size(C);
result=zeros(rows,col_B*col_C);
for i=1:col_B
for j=1:col_C
result(:,(i-1)*col_C+j)=A+B(:,i)+C(:,j);
end
end
11 件のコメント
Niels
2017 年 1 月 24 日
the result will be that large, so even if the calculations are minimzed, the problem with the size of the result is still the same.
this might help you o set the limit higher https://de.mathworks.com/help/matlab/matlab_env/set-workspace-and-variable-preferences.html
その他の回答 (1 件)
John Chilleri
2017 年 1 月 24 日
編集済み: John Chilleri
2017 年 1 月 24 日
Hello,
I only tested this with your example and it worked, but I think it's generally correct:
%
% Strangely adding matrices
%
function D = strangelyAddingMatrices(A,B,C)
n = size(C,2);
nB = size(B,2);
for i = 1:n
C(:,i) = C(:,i)+A;
end
D = [];
for i = 1:nB
C2 = C;
for j = 1:n
C2(:,j) = C2(:,j)+B(:,i);
end
D = [D C2];
end
end
Hope this helps!
9 件のコメント
John Chilleri
2017 年 1 月 24 日
What do you mean by minimum sum? Like which columns summed produce the minimum? Or something else?
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