Replacing repeated values in each row with zero

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Ismaeel
Ismaeel 2017 年 1 月 7 日
編集済み: Image Analyst 2017 年 1 月 7 日
I have a matrix A:
A=[ 2 4 6 7 8 9 10 28 6 9 10 11;
2 4 6 7 8 9 10 28 10 21 22 24]
and I want to delete any repeated element in each row. The result should be as:
A=[ 2 4 6 7 8 9 10 28 0 0 0 11;
2 4 6 7 8 9 10 28 0 21 22 24]
Any idea? Thanks

回答 (1 件)

Image Analyst
Image Analyst 2017 年 1 月 7 日
Why do you want to do this? Is it homework? Are all A integers, or can they have fractional parts? Have you considered using histcounts() and look for numbers where the count is more than 2?
  2 件のコメント
Ismaeel
Ismaeel 2017 年 1 月 7 日
Thank you for the reply. No, it's not homework. The reason I want to do so is that each row has been created from previous processes and when I combine them (two rows combined to get the rows above), I get some of these repeated elements. The matrix I have is much greater in size than the one I mentioned. I haven't tried that function yet.
Ismaeel
Ismaeel 2017 年 1 月 7 日
I forgot to add that all A are integer values, no fractional parts in it.

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