How to take elements row wise or column wise in a 2d array

A is a 5*5 array. Its needed to take 7 elements along the 1st column and 2 from the beginning of 2nd column.So the window size is 7.Now that makes it possible to take 3 windows.So 4 elements are left.this last window should be 4 leftover elements and rest zeroes.How to have a loop that gives me the 4 windows in a variable

3 件のコメント

per isakson
per isakson 2016 年 12 月 31 日
Without a loop
>> A=magic(5);
>> reshape( [A(:);zeros(3,1)], [7,4] )
ans =
17 6 25 16
23 12 8 22
4 18 14 3
10 1 20 9
11 7 21 0
24 13 2 0
5 19 15 0
MSP
MSP 2017 年 1 月 1 日
編集済み: per isakson 2017 年 1 月 1 日
But can u pls generalize it
per isakson
per isakson 2017 年 1 月 1 日
In your question you say
  • "a 5*5 array" &nbsp
  • "take 7 elements [window] along" &nbsp
  • "that gives me the 4 windows in a variable" &nbsp
  • "matrix signalprocess" &nbsp
"generalize" &nbsp Yes, but in what way? Arbitrary size of the input matrix and/or the window? Along columns or rows? ...

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Walter Roberson
Walter Roberson 2016 年 12 月 31 日

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1 件のコメント

Walter Roberson
Walter Roberson 2017 年 1 月 1 日
window = 7;
A = randi(5,5);
n = numel(A);
left_over = mod(n, window);
if left_over == 0
stream = A(:);
else
stream = [A(:); zeros(window - left_over, 1)];
end
output = reshape(stream, window, []);

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