How do I find the maximum/last index value from a list of indices

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Alex
Alex 2016 年 12 月 24 日
回答済み: Alex 2017 年 3 月 18 日
I have imported some data to form an array called 'newData1.data' and then find the row/col indices for each value 1-49 in a vector called 'numbers'
numbers=1:1:49;
for i=1:length(numbers)
[row,col] = find(newData1.data' == i);
end
How do I find the greatest/maximum/last column number?
test(i) = max(col)
does not work within the loop. There are plenty of questions and answers on how to get the indices of the maximum value in the array, but that is not what I am looking for.
Best regards,
Alex

採用された回答

Image Analyst
Image Analyst 2016 年 12 月 24 日
Try this:
numbers = 1 : 1 : 49;
for k = 1 : length(numbers)
[rows, columns] = find(newData1.data' == numbers(k));
maxColumns(k) = max(columns)
end
  2 件のコメント
Alex
Alex 2016 年 12 月 24 日
This is the same thing I was doing. It returns the error, "Index exceeds matrix dimensions."
Image Analyst
Image Analyst 2016 年 12 月 24 日
It's not exactly the same thing you were doing since my code is more robust in that it compares "numbers" instead of i. Your code defines numbers but then never uses it. Anyway there is nothing wrong so the only way we can continue is if you attach your data via a .mat file.

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その他の回答 (1 件)

Alex
Alex 2017 年 3 月 18 日
Solution: I found that I created a variable called min/max: max=max(data) min=min(data) By changing these lines to: dmax=max(data) dmin=min(data) the max(idx), min(idx) function as expected.

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