I want a image matrix 512x512 to be represented in the array form or simply in a straight line while scanning the matrix in inverse S way. I have attached an image to make it clear

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David Barry
David Barry 2016 年 12 月 22 日
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akash bais
akash bais 2016 年 12 月 22 日

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Roger Stafford
Roger Stafford 2016 年 12 月 22 日
編集済み: Roger Stafford 2016 年 12 月 22 日

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Here are the “Pixel Scan” and “Rearrange” operations:
% Let M be the m by n image matrix
% Pixel Scan:
M = M.';
M(:,2:2:end) = flipud(M(:,2:2:end)); % Flip even columns
M = M(:); % The result is a column vector
Then perform the “Difference computation”, the “Histogram shifting” and the “Embedding” on M.
% Now M is still a column vector
% Rearrange:
M = reshape(M,n,m); % <-- Note the reversal of sizes here
M(:,2:2:end) = flipud(M(:,2:2:end)); % Flip even columns
M = M.';
% M is again an m by n image matrix.
The "Difference computation" is an obvious use of the ‘diff’ function. I have no idea how to do the “Histogram shifting” or the “Embedding”.

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