How can I use the chirp function to create a linear sine sweep from a given starting and ending frequency within a given time frame?

20 ビュー (過去 30 日間)
How could I, for example, make a 3 second sine sweep starting at 40 Hz and ending at 10 kHz?
The examples given in the help section for chirp have not been useful.

回答 (1 件)

David Barry
David Barry 2016 年 12 月 13 日
% create time signal
freqSamp = 1e6;
tStart = 0;
tEnd = 3;
t = tStart:1/freqSamp:tEnd;
% create swept sine
freqStart = 40;
freqEnd = 1e4;
phaseInit = -90;
method = 'linear';
y = chirp(t, freqStart, tEnd, freqEnd, method, phaseInit);
  4 件のコメント
Atilla Golan
Atilla Golan 2018 年 1 月 29 日
It does work perfectly, I have two questions: 1- What is the role of phaseinit? I changed it to different values and nothing changed. 2- It is up-going linear, how we can make down-going one?
Greg Dionne
Greg Dionne 2018 年 1 月 29 日
Try something like this:
t=0:0.001:2; % 2 secs @ 1kHz sample rate
y=chirp(t,200,1,100,'linear'); % Start @ 200Hz, cross 100Hz at t=1sec
spectrogram(y,kaiser(128,18),120,128,1E3,'reassigned','yaxis');
title('Linear Chirp: start at 200Hz and cross 100Hz at t=1sec');

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