how to plot a tangent line of specific point (x,y) of function y=x^2+2?

120 ビュー (過去 30 日間)
Tsvi Weiss
Tsvi Weiss 2016 年 12 月 10 日
回答済み: Image Analyst 2016 年 12 月 10 日
I trying to obtain the tangent equation and draw the line from specific points (x,y) of the function y=x^2+2 and show them on a figure.

採用された回答

Image Analyst
Image Analyst 2016 年 12 月 10 日
Try this:
x = linspace(-2, 2, 500);
y = x .^ 2 + 2;
plot(x, y, 'b-', 'LineWidth', 2);
grid on;
fontSize = 20;
xlabel('X', 'FontSize', fontSize);
ylabel('Y', 'FontSize', fontSize);
ylim([0, 7]);
% Pick a point at -1 (or wherever) and plot the tangent
xTangent = -1;
% Equation of the tangent is y = slope*x + offset
% From the equation y=x^2 we know the slope is 2*x.
% Find the slope at x = xTangent.
slope = 2 * xTangent;
% We want to plot the tangent line where it just touches the curve,
% so we need to know the y value at xTangent.
yTangent = xTangent .^ 2 + 2; % Y value of curve at x = xTangent.
hold on;
plot(xTangent, yTangent, 'r*', 'LineWidth', 2, 'MarkerSize', 10);
% Use point slope formula of a line to get equation for y
% y-y0 = slope*(x-x0).
% y = slope * (x - xTangent) + yOffset
yTangentLine = slope * (x - xTangent) + yTangent;
plot(x, yTangentLine, 'b-', 'LineWidth', 2);

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeGraphics についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by