how can i patch a circle in the origin of the axis?

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juan diego villada
juan diego villada 2016 年 12 月 7 日
コメント済み: Iddo Weiner 2016 年 12 月 8 日
wich cordinates can i use
  3 件のコメント
Iddo Weiner
Iddo Weiner 2016 年 12 月 8 日
Glad to help..
If you could accept an answer it would be of help for the next people who read this question.. My answer is given below, and KSSV's answer is essentially the same so - whichever one, it doesn't really matter...
Good luck

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回答 (2 件)

KSSV
KSSV 2016 年 12 月 8 日
clc; clear all ;
R = 1 ;
th = linspace(0,2*pi) ;
x = R*cos(th) ;
y = R*sin(th) ;
patch(x,y,'r') ;
axis equal

Iddo Weiner
Iddo Weiner 2016 年 12 月 8 日
See my initial answer, I posted it as a comment by mistake:
rad = 10; %this is the radius (change it if you like)
angle = 0:0.001:2*pi; % a full circle range
x_cord = rad*cos(angle);
y_cord = rad*sin(angle);
plot(x_cord, y_cord);
hold on
plot(xlim,[0 0])
plot([0 0],ylim)
hold off

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