Find the x value from a specific iteration of fmincon

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boureghda mohammed
boureghda mohammed 2016 年 12 月 5 日
編集済み: Massimo Zanetti 2016 年 12 月 13 日
How can I extract the the value of x at the iteration 5 when f(x)= 0.300877 after the optimization procedure.
Max Line search Directional First-order
Iter F-count f(x) constraint steplength derivative optimality Procedure
0 3 1 -1
1 9 0.953127 -0.9375 0.125 -2 12.5
2 16 0.808446 -0.8601 0.0625 -2.41 12.4
3 21 0.462347 -0.836 0.25 -12.5 5.15
4 24 0.340677 -0.7969 1 -4.07 0.811
5 27 0.300877 -0.7193 1 -0.912 3.72
6 30 0.261949 -0.6783 1 -1.07 3.02
7 33 0.164971 -0.4972 1 -0.908 2.29
8 36 0.110766 -0.3427 1 -0.833 2

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Massimo Zanetti
Massimo Zanetti 2016 年 12 月 5 日
編集済み: Massimo Zanetti 2016 年 12 月 13 日
From the help page about Output Functions Output Functions you can extract this way to save iterates of the solver. Assume you want to minimize the function f(x1,x2) = 4*x1^2 + 2*x2^2, then:
  1. Define your problem by nesting functions into one main function:
function [x fval history] = myproblem(x0)
history = [];
options = optimset('OutputFcn', @myoutput);
[x fval] = fminsearch(@objfun, x0,options);
function stop = myoutput(x,optimvalues,state);
stop = false;
if isequal(state,'iter')
history = [history; x];
end
end
function z = objfun(x)
z = 4*x(1)^2+2*x(2)^2;
end
end
  1. Trigger the solver (with one starting value x0) and retrieve all iterates the solver has computed in the matrix history
x0 = [1,2];
[x,val,history] = myproblem(x0);
Inspect matrix history, each row is the k-th iterate. The same procedure works for fmincon.

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