How to return the row vector containing the highest values from a matrix?
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Hi, I can't seem to find a solution to this but it's a pretty simple problem. Say I have a matrix:
M = [10 9 11 7 8;
10 9 8 7 6;
9 6 7 8 5]
What I want to do is to somehow extract the row vector which holds the largest sequence. I have tried the max() function but it just doesn't retain the individual rows. It is important that it returns a specific row vector from M.
The rows won't always necessarily be sequential like this, so I cannot just use the row that sums to the largest value either.
Thanks
2 件のコメント
James Tursa
2016 年 11 月 22 日
Please define "largest sequence" for us. What is the exact criteria you want for this? What would be returned for your example above?
採用された回答
Image Analyst
2016 年 11 月 22 日
Try this:
M = [13 9 8 7 6;
13 12 11 9 8;
13 11 5 3 2]
% Find the maxima in each column independently.
columnMaxima = max(M, [], 1)
% Now sort in decending order.
columnMaxima = sort(columnMaxima, 'Descend')
6 件のコメント
Image Analyst
2016 年 11 月 22 日
The second, optional output of max supplies the index from which the max value came from. Use it.
その他の回答 (1 件)
dpb
2016 年 11 月 22 日
Sort first by row (already done here in these examples), then by column, retaining the sort index. Then (I think, altho didn't prove concluseively) the row will be minimum of the sum of those indices (fewest permutations to arrange).
>> [~,ix]=sort(M,1);
>> [~,ix]=min(sum(ix,2))
>> M(ix,:)
ans =
13 12 11 9 8
>>
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